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  • David

    I think that is e^(i*pie)

    The last part is an infinite geometric series that converges to 1 (http://en.wikipedia.org/wiki/Geometric_progression)

    \frac12 \frac14 \frac18 \frac{1}{16} \cdots=\frac{1/2}{1-( 1/2)} = 1.

    That gives:
    e^{i*pi} 1 = 0 which is Euler’s identity (http://en.wikipedia.org/wiki/Euler's_identity)

    Looks like those Bitches be getting .002 0 = $0.002

  • David

    I think thats i*pi

    The last part is an infinite geometric series that converges to 1 (http://en.wikipedia.org/wiki/Geometric_progression)

    \frac12 \frac14 \frac18 \frac{1}{16} \cdots=\frac{1/2}{1-( 1/2)} = 1.

    That gives:
    e ^ (i * pi) 1 = 0 which is Euler’s identity (http://en.wikipedia.org/wiki/Euler's_identity)

    Looks like those Bitches be getting .002 0 = $0.002

  • http://elegantcode.com dcarver

    The memo is pretty good. :-) .

  • Jason Walker

    Ok… so this is old, but also, the text below the image is erroneous.

    e^i(pi) is what the check should read, which is equal to -1.

    So the check is made out for 2 tenths of a cent. which is a response to the verizon math fiasco – the one where the CSR could not understand there is a difference between 2/10ths of a cent and 2 cents.

    http://www.verizonmath.com/

  • http://www.ticklefilms.com David Starr

    Did this check ever pay out?